find the zeroes of the polynomial x4-3x3+6x-4, if two of zeroes are √2&-√2
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Answer:
x⁴+3x³+6x-4.
x=√2.
(√2)⁴+3(√2)³+6(√2)-4.
4+3(2.83)+6√2-4. (Because (√2)⁴=4 & (√2)²=2).
4+8.49+6√2-4.
8.49+6√2.
x=-√2.
(-√2)⁴+3(-√2)³+6(-√2)-4.
-4+3(-2.83)-6√2-4. (Because +×-=-).
-4-8.49-6√2-4.
-8-8.49-6√2. (Because -×-=+ & largest number is important).
-16.49-6√2.
I think this is your answer.
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