Question

find the zeroes of the polynomial 'xsquare-3'

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Answer 1

Step-by-step explanation:

xsquare -3 = xsquear -(√3square)

= ( x + √3 ) (x - √3

√3 = 3

a(sq)-b(sq)=(a+b)(a-b)

x(sq)-3= x(sq)+0x-3

x+ √3 = 0. | x- √3 = 0

x= -√3 | x =√3

sum of 0= (√3) + (-√3). product of 0= (√3x-√3)

=√3- √3 = 0/1. = -√3

= -( cofficient of x)/. =. -3

cofficient of x (sq). = -3/1

( sq means raise to the power 2)

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Answer 2

Answer:

Step-by-step explanation:

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