find the zeroes of the polynomial xsquare - 3 and verify the relationship between the zeroes and the coefficient
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Answer:
2 is the zero of the polynomial
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Step-by-step explanation:
Given polynomial is x²−3
Here, a=1,b=0 and c=−3
x²−3=(x−root3)(x−root3)
So, the value of x²−3 is zero when x=root3 or x=−root3
Threrfore , thr zeroes of x²−3 are 3 and −3.
Now, sum of zeroes =root3−root3=0=10/1=−b/a
product of zeroes =(root3)(−root3)=−3=−3/1=c/a
Hence verified.
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