Find the zeroes of the polynomials.
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Step-by-step explanation:
7y² - 11/3y - 2/3 = 0
21y² - 11y - 2 = 0 [ taking 3 as LCM ]
21y² + 3y - 14y - 2 = 0
3y ( 7y + 1 ) - 2 ( 7y + 1 ) = 0
( 7y + 1 ) ( 3y - 2 ) = 0
7y + 1 = 0 or 3y - 2 = 0
7y = -1 or 3y = 2
y = -1/7 or 2/3
zeroes of the polynomial 7y² - 11/3y - 2/3 are -1/7 and 2/3.
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