Question

find the zeroes of the polynomials mx^2+(m+n)x+n​

Answer 1

Step-by-step explanation:

mx^2+(m+n)x+n

Solving by splitting the middle term method,

mx^2+mx+nx+n

Taking mx common ,

mx(x+1)+nx+n

Taking n common,

mx(x+1)+n(x+1)

Zeroes=

mx+n=0

x=-n/m

Also,

x+1=0

x=-1

Answer 2

Answer:

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