Find the zeroes of the polynomials of 10x²+3x-1
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Answer:
-1/2 or 1/5
Step-by-step explanation:
given that p(x) = 10x^2+3X-1 =0
=10x^2+5x-2x-1 =0
common 5x we get 5x(2x+1) -2x-1
=(5x-1)(2x+1) =0
=5x-1=0 or 2x+1=0
x= -1/2or 1/5
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