Question

find the zeroes of the polynomials p (x)=x^2-7x+6​

Answer 1

Answer:

$x = 1 \: \: \: \: or \: \: \: \: \: x = 6.$

Step-by-step explanation:

${x}^{2} - 7x + 6 = 0 \\ \\ {x}^{2} - 6x - x + 6 = 0 \\ \\ x(x - 6) - 1(x - 6) = 0 \\ \\ (x - 1)(x - 6) = 0 \\ \\ x = 1 \: \: \: \: or \: \: \: \: \: x = 6.$