Question

find the zeroes of the polyonomial 6x²-3-7x
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Answer 1

$\huge\bold\star\blue{ Answer:}\star$

$6x^{2}– 3 – 7x$

$\text\orange{By rearranging, we get:}$

$6x^{2}-7x-3$

$6x^{2}-9x+2x-3$

$3x(2x-3)+1(2x-3)$

$(3x+1) (2x-3)$

$\star\blue{ Zeros \:are :}\star </p><p>$

$\text\purple{x= -1/3 and x= 2/3:}$

Answer 2

Answer:

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