find the zeroes of the quadratic 4 root 3 x²+5x-2root3 and verify the relationship between the zeroes and the coffecients
Answers
Answered by
4
hi!!______
___________.
here Is your answer
___________.
here Is your answer
Attachments:
Answered by
6
Hiii friend,
P(X) => 4✓3X²+5X-2✓3
=> 4✓3X²+8X-3X-2✓3
=> 4X(✓3X+2) -✓3(✓3X+2)
=> (✓3X+2)(4X-✓3) = 0
=> (✓3X+2) = 0 OR (4X-✓3) = 0
=> X = -2/✓3 OR X = ✓3/4
Alpha = -2/✓3 and beta = ✓3/4
Relationship between the zeroes and Coefficient.
Sum of zeroes = (Alpha + Beta) = (-2/✓3 + ✓3/4) = -8+3/4✓3 = -5/4✓3 = Coefficient of X/Coefficient of X².
And,
Product of zeroes = (Alpha × beta) = -2/✓3 × ✓3/4 = -2✓3/4✓3 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU...... :-)
P(X) => 4✓3X²+5X-2✓3
=> 4✓3X²+8X-3X-2✓3
=> 4X(✓3X+2) -✓3(✓3X+2)
=> (✓3X+2)(4X-✓3) = 0
=> (✓3X+2) = 0 OR (4X-✓3) = 0
=> X = -2/✓3 OR X = ✓3/4
Alpha = -2/✓3 and beta = ✓3/4
Relationship between the zeroes and Coefficient.
Sum of zeroes = (Alpha + Beta) = (-2/✓3 + ✓3/4) = -8+3/4✓3 = -5/4✓3 = Coefficient of X/Coefficient of X².
And,
Product of zeroes = (Alpha × beta) = -2/✓3 × ✓3/4 = -2✓3/4✓3 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU...... :-)
Similar questions