Question

Find the zeroes of the quadratic formula 6x^2-3-7x​

Answer 1

Answer:

6x^2-7x-3=0

6x^2+2x-9x-3=0

2x(3x+1)-3(3x+1)=0

2x-3=0                   3x+1=0

x=3/2                      x= -1/3

3/2 and -1/3 are the zeroes of the polynomial

Step-by-step explanation:

Answer 2

Step-by-step explanation:

6x²-7x-3

6x²-9x+2x-3(Product of 6 and 3, should give the sum of the middle term, i.e., 6×-3 = -18 = -9+2= -7).

3x(2x-3)+1(2x-3)

(3x+1)(2x-3)

x= -⅓ and x=3/2.

Hence, the positive is the answer, i.e, 3/2.