Question

Find the Zeroes of the quadratic polinomial x²- 4x - 117​

Answer 1

Answer:

-9 and 13

Step-by-step explanation:

Put p(x) = 0.

x² - 4x - 117 = 0

x² - (13 - 9)x -117 = 0

x² + 9x -13x -117 = 0

x(x+9) -13(x+9) = 0

(x+9) (x-13) = 0

The given polynomial has two zeroes:

• x+9 = 0 => x = -9
• x-13 = 0 => x = 13

Answer 2

Hope this may help you.....

X= 13

X= -9