Question

Find the Zeroes of the quadratic
polynamial
x2 + 7x + 12 ,and verify the relation
between the zeroes
its co-effecients
​

Answer 1

Answer:

-4 and -3

Step-by-step explanation:

By factor method break coefficient of x such that it's sum gives original coefficient of x and on multiplying is equal to product of constant and coefficient of x^2.

=>x^2+7x+12=0

4+3=7 and 4×3=12×1

=>x^2+3x+4x+12=0

=>x(x+3) +4(x+3)=0 {taking common}

=>(x+4)(x+3)=0

=>x= -4, or x= -3

We know,

If roots are y and z

Then,

y+z=-(coefficient of x)/(coefficient of x^2)

y×z=(constant)/(coefficient of x^2)

=>y+z=-7=-(7)/1 [proved]

=>y×z=12=12/1 [proved]

Hope it helps...

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