Question

find the zeroes of the quadratic polynomial 10x²+3x+1 and verify the relationship between zeroes and coefficients​

Answer 1

Answer:

given

p(x) = 10x²+3x-4

10x²+8x-5x-4

2x(5x+4)-1(5x+4)

(2x-1)(5x+4)

2x-1 = 0

2x = 1

x = 1/2

5x+4 = 0

5x = 4

x = 4/5

zeroes are 1/2 & 4/5

verification between zeroes and coefficients

α = -b/a

1/2 = -3/10

β = c/a

4/5 = -4/10

4/5 = -2/5

Step-by-step explanation:

Answer 2

Answer:

10x^2+3x+1

10x^2+5x-2x+1

5x(2x+1)-1(2x+1)

(5x-1) (2x+1)