Question

find the zeroes of the quadratic polynomial 2x^2 - 9 , and verify the relationship between the zeroes and its coefficients.

Answer 1

Step-by-step explanation:

$2 {x}^{2} - 9 = 0$

$2 {x}^{2} = 9$

${x}^{2} = \frac{9}{2}$

$x = \frac{3}{ \sqrt{2} } or \: \: \: - \frac{3}{ \sqrt{2} }$

let these zeroes be alpha and beta

then

$\alpha + \beta = 0 = \frac{ - b}{a}$

$\alpha \beta = - \frac{9}{2} = \frac{c}{a}$