Question

Find the zeroes of the quadratic polynomial 2x²-18x+40 and verify relationship between zeroes and coefficient

Answer 1

Step-by-step explanation:

2x^2-10x-8x+40

2x(x-5)-8(x-5)

(2x-8)(x-5).

x€{4,5}

Sum of roots=5+4=9

verification:(-b/a)=18/2=8

Product of roots=5×4=20

verification:(c/a)=40/2=20.

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Answer 2

Step-by-step explanation:

» 2x² - 18x + 40

» 2x² - 10x - 8x + 40

» 2x (x - 5) - 8 (x -5)

» (2x - 8) (x - 5)

ZEROES ARE GIVEN BY :

2x - 8 = 0

x = 8 / 2

x = 4

OR

x - 5 = 0

x = 5

VERIFICATION :

Sum of Zeros : 4 + 5 = 9

- (Coefficient of x) / (Coefficient of x²) = 18 / 2 = 9

.

.

Product of Zeros = 4 * 5 = 20

(Constant term) / (Coefficient of x²) = 40 / 2 = 20

Hence Verified...