Question

Find the zeroes of the quadratic polynomial 2x² - 2√2x - 3

Answer 1

Step-by-step explanation:

Refer the attachment.......

Answer 2

x=1/√2 and x= -3/√2

$2 {x}^{2} - (3 \sqrt{2x} - \sqrt{2x} ) - 3 \\ 2 {x}^{2} - 3 \sqrt{2x} \: \: \: \: \: \: - \sqrt{2x} - 3 \\ \: \sqrt{2x} ( \sqrt{2x} + 3) \: \: \: \: - 1( \sqrt{2x} + 3) \\ factors \: are = > \\ (\sqrt{2x} + 3) \: \: \: \: \: \: \: \: \: \: \: ( \sqrt{2x} - 1) \\ \\ \\ when \: \: \: \: \sqrt{2x} - 1 = 0 \\ \sqrt{2x} = 1 \\ x = \frac{1}{ \sqrt{2} } \\ \\ \\ when \: \: \: \sqrt{2x } + 3 = 0 \\ \sqrt{2x } = - 3 \\ x = \frac{ - 3}{ \sqrt{2} }$