Find the zeroes of the quadratic polynomial 2x² - 25
Answers
Answered by
3
Answer:
see the given attachment
Attachments:
Answered by
5
2x^2-25
(2x)^2-(5)^2
a^2-b^2=(a+b)(a-b)
(root2x+5)(root2x-5)
(root2x+5)=0
x=-5/root2
Similar questions