Question

Find the zeroes of the quadratic polynomial 2x2-7x+5 and verify the relationship bet ween the zeroes and coefficients

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

$\huge \green { \bigstar{ \underline{ÀNSWER}}}$

$2 {x}^{2} -7x+5 \\ \\ {2x}^{2} - 2x - 5x + 5 \\ \\ 2x(x - 1) - 5(x - 1) \\ \\ (2x - 5)(x - 1) \\ \\ x = \frac{5}{2} \\ x = 1 \\ \\ \alpha = \frac{5}{.2} \\ \beta = 1 \\ \\ \alpha + \beta = \frac{ - b}{a} \\ \\ in \: which \\ a = 2 \\ b = - 7 \\ c = 5 \\ \alpha + \beta = - \frac{b}{a} \\ \frac{5}{2} + 1 = \frac{ - ( - 7)}{2} \\ \\ \frac{5 + 2}{2} = \frac{7}{2} \ \\ \frac{7}{2} \\ \\{ \huge \blue { \bigstar{ \underline{verified}}}} \\ \\ \alpha \beta = \frac{c}{a} \\ \frac{5}{2} \times 1 = \frac{5}{2} \\ \\ \frac{5}{2} = \frac{5}{2} \\ \\ \huge \red { \bigstar{ \underline{verified}}}$

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