Find the zeroes of the quadratic polynomial 2x2–9 = 0, and verify the relation between the zeroes and its coefficients
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Let p(x)=2x
2
−(3k+1)x−9
Let α,β be the roots of this polynomial.
We know that
α+β=
2
3k+1
= Sum of the roots
αβ=
2
−9
= Products of the roots
Given that : One zero is negative of the other
⇒α=−β
⇒α+β=0
⇒α+β=
2
3k+1
=0
⇒3k+1=0
⇒k=−
3
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Answer:
Find the zeroes of the quadratic polynomial 2x2–9 = 0, and verify the relation between the zeroes and its coefficients
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