Question

Find the zeroes of the quadratic polynomial √3 x2 – 8x + 4√3. (2013)​

Answer 1

Answer:

p(x) =√3x2-8x+4√3

√3x2-6x-2x+4√3

√3x(x-2√3)-2(x-2√3)

(√3x-2)(x-2√3)

therefore x= 2/√3 or 2√3