Question

Find the zeroes of the quadratic polynomial 3 x2 − 8x + 4​

Answer 1

Answer:

zeroes of the quadratic polynomial are 3x²-8x+4 are 3/2, 2

Step-by-step explanation:

3x²-8x+4=0

3x²-x(6+2)+4=0

3x²-6x-2x+4=0

3x(x-2)-2(x-2)=0

(3x-2)(x-2)=0

3x-2=0 3x=2 x=3/2

x-2=0 x=2

x=3/2, 2

zeroes of the quadratic polynomial are 3x²-8x+4 are 3/2, 2

Answer 2

Step-by-step explanation:

$3 {x}^{2} - 8x + 4 \\ = 3 {x}^{2} - 6x - 2x + 4 \\ = 3x(x - 2) - 2(x - 2) \\ = (3x - 2)(x - 2) \\ 3x = 2 \\ x = \frac{2}{3} \: and \\ x = 2$