Question

Find the zeroes of the quadratic polynomial 3x 2 + 16x + 13.

Answer 1

Answer:

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Answer 2

Answer:

heya mate ☺

$3x^{2} + 16x + 13 = 0 \\ = > 3x ^{2} + (13 + 3)x + 13 = 0 \\ = > 3x ^{2} + 13x + 3x + 13 = 0 \\ = > x(3x + 13) + 1(3x + 13) = 0 \\ = > (3x + 13)(x + 1) = 0 \\ either \: 3x + 13 = 0 \\ = > 3x = - 13 \\ = > x = \frac{ - 13}{3} \\ or \: x + 1 = 0 \\ = > x = - 1$

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