Question

Find the zeroes of the quadratic polynomial √3x^2-8x+4√3​

Answer 1

Answer:

Step-by-step explanation:

√3x² -8x+ 4√3

= √3x² -6x-2x+4√3

=√3x ( x- 2 √3) -2 ( x - 2√3)

= (√3x-2)(x-2√3)

so, x = 2/√3 , 2√3

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