Question

find the zeroes of the quadratic polynomial 3x^2 - x - 4

Answer 1

Answer:

3x² - x - 4

= 3x² + 3x - 4x -4

= 3x ( x+1 ) -4 ( x+1 )

= ( 3x-4 )( x+1)

therefore

either x= 4/3

or -1

Answer 2

Answer:

$\\ \tt \: 3 {x}^{2} - 4x + 3x - 4 \\ \\ \\ \implies \tt \: x \: (3x - 4) \: + 1 \: (3x - 4) \\ \\ \\ \implies \tt \: (x + 1) \: (3x - 4)$

So , zeroes are 4/3 and -1

$\\ \tt \: 3x - 4 = 0 \\ \\ \implies \tt \: x = \frac{4}{3}$

or,

$\\ \tt \: x + 1 = 0 \\ \\ \implies \tt \: x = -1$