Question

Find the zeroes of the quadratic polynomial 3x2 +11x-4 and verify
the relationship between the zeroes and the coefficients.​

Answer 1

Step-by-step explanation:

For the zeros of 3x^2+11x-4,

3x^2+11x-4= 0

→3x^2 +12x-x-4=0

→3x(x+4)-1(x+4)=0

→(3x-1)(x+4)=0

→3x-1=0

or , x+4=0

→x=1/3 or , -4

Hence , required zeros are -1/3 and -4 .

Now , Verification

1)sum of zeros = 1/3-4= -11/4 = -b/a

2)Product of zeros= -4/3= c /a

Answer 2

Answer:

zeros of the polynomial are 1/3, -4

Step-by-step explanation:

p(x)=3x^2+11x-4

=(3x-1) (x+4)

p(x)=0 then x=1/3 , x=-4

Relationship between the zeros:

Sum of the zeros=(-coefficient of x)/ (coefficient of x^2)

Product of the zeros= constant term / (coefficient of x^2)