Find the zeroes of the quadratic polynomial 3x2 – 2.
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explanation step by step: Given, Quadratic polynomial p(x) = 3x²-2. i) To find the zeroes of p(x) we take p(x)=0. 3x²-2 = 0. => 3x² = 2. => x² = 2/3. => x = ±√(2/3) Verification: Let m,n are two zeroes of the polyomial, m = -√(2/√3)and n = √(2/3) Compare p(x) with ax²+bx+c , we get. a = 3 , b = 0 , c=-2.
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