find the zeroes of the quadratic polynomial 3x2-3√3x+2andverify the relationship between the zeroesand the coeffcients
Shanaya01:
could you please tell the question clearly
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Answered by
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Heya !!!
P(X) = 3X² -3✓3X +2
=> 3X² - 2✓3X - ✓3X +2
=> ✓3X ( ✓3X - 2) -1( ✓3X -2)
=> ( ✓3X -2) ( ✓3X -1) = 0
=> ( ✓3X-2) = 0 OR ( ✓3X -1) = 0
=> X = 2/✓3 OR X = 1/✓3
Let Alpha = 2/✓3 and Beta = 1/✓3
Relationship between the zeroes and Coefficient.
Sum of zeroes = Alpha + Beta = 2/✓3 + 1/✓3 = 2✓3 + ✓3/3 = Coefficient of X/Coefficient of X².
And,
Product of zeroes = Alpha × Beta = 2/✓3 × 1/✓3 = 2/✓3 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU..... :-)
P(X) = 3X² -3✓3X +2
=> 3X² - 2✓3X - ✓3X +2
=> ✓3X ( ✓3X - 2) -1( ✓3X -2)
=> ( ✓3X -2) ( ✓3X -1) = 0
=> ( ✓3X-2) = 0 OR ( ✓3X -1) = 0
=> X = 2/✓3 OR X = 1/✓3
Let Alpha = 2/✓3 and Beta = 1/✓3
Relationship between the zeroes and Coefficient.
Sum of zeroes = Alpha + Beta = 2/✓3 + 1/✓3 = 2✓3 + ✓3/3 = Coefficient of X/Coefficient of X².
And,
Product of zeroes = Alpha × Beta = 2/✓3 × 1/✓3 = 2/✓3 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU..... :-)
Answered by
20
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