Question

Find the zeroes of the quadratic polynomial:
3x2 + 5x + 2

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Value\:of\:x=-1\:and\:\frac{-2}{3}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies {3x}^{2} + 5x + 2 = 0 \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Value \: of \: x = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\\tt: \implies {3x}^{2} + 5x + 2 = 0 \\ \\ \tt: \implies {3x}^{2} + 3x + 2x + 2 = 0 \\ \\ \tt: \implies3x(x + 1) + 2(x + 1) = 0 \\ \\ \tt: \implies(3x + 2)(x + 1) = 0\\ \\ \green{\tt: \implies x = - 1 \: and \: \frac{ - 2}{3}} \\ \\ \bold{Alernate \: method} \\ \tt: \implies x = \frac{ - b \pm \sqrt{ {b}^{2} - 4ac} }{2a} \\ \\ \tt: \implies x = \frac{ - 5 \pm \sqrt{ {5}^{2} - 4 \times 3 \times 2 } }{2 \times 3} \\ \\ \tt: \implies x = \frac{ - 5 \pm \sqrt{1} }{6} \\ \\ \tt: \implies x = \frac{ -5 \pm1}{6} \\ \\ \green{\tt: \implies x = - 1 \: and \: \frac{ - 2}{3} }$

Answer 2

$\large \underline{ \blue{ \boxed{ \bf \green{Required \: Answer}}}}$