Question

Find the zeroes of
the quadratic
polynomial √3x² - 8x + 4√3​

Answer 1

Step-by-step explanation:

ANSWER =

P(0) = √3 × (0)² - 8×0 + 4√3

P(0) = 0-0+4√3

P(0) = 4√3

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Answer 2

Answer:

in this polynomial

a= √3 , b= -8 , c= 4√3

Discriminant D = b²-4ac

= 64-48

= 16

So, by quadratic formula

x = -b+√D/2a. Or. x = -b - √D/2a

= 8+4/2√3 Or. x = 8-4/2√3

= 12/2√3. Or. = 4/2√3

= 2√3. Or. = 2/√3