Question

Find the zeroes of the quadratic polynomial 3x2 – x – 4

Answer 1

3x² - x - 4 = 0

3x² + 3x - 4x - 4 = 0

3x(x + 1) - 4(x + 1) = 0

(3x - 4)(x + 1) = 0

x = 4/3 or x = -1

Answer 2

$\huge\underline\mathfrak\purple{Solution}$

3x² - x - 4

3x² + 3x - 4x - 4

3x ( x + 1 ) - 4 ( x + 1 )

( 3x - 4 ) ( x + 1 )

Thanks!! ❤