find the zeroes of the quadratic polynomial 3x2-x-4 and verify the relationship between the zeroes and coefficient.
Answers
Solution
Given :-
- Equation, 3x² - x - 4 = 0
Find :-
- Its roots
Explanation
Let,
P & Q be roots of this Equation.
Using Formula
★ Sum of roots = - ( Coefficient of x)/(coefficient of x²)
★ product of roots = (constant part)/(coefficient of x²)
So, keep above Value,
==> sum of roots = -(-1)/3
==> P + Q = 1/3____________(1)
And,
==> Product of roots = -4/3
==> P.Q = -4/3
==> P = -4/(3Q)____________(2)
keep in equ(1)
==> -4/(3Q) + Q = 1/3
==> (-4 + 3Q² ) × 3 = 3Q
==> 9Q² - 3Q - 12 = 0
==> 3Q² - Q - 4 = 0
==> 3Q² - 4Q + 3Q - 4 = 0
==> Q(3Q - 4) + 1(3Q - 4) = 0
==> (3Q - 4)(Q + 1)= 0
==> 3Q - 4 = 0 Or, Q + 1 = 0
==> Q = 4/3 Or, Q = -1
keep value of Equation (1)
When,
- Q = 4/3
==> P + 4/3 = 1/3
==> P = 1/3 - 4/3
==> P = (1- 4)/3
==> P = -3/3
==> P = -1
When,
- Q = -1,
==> P - 1 = 1/3
==> P = 1/3 + 1
==> P = (1 + 3)/3
==> P = 4/3
Since
- Roots will be of this Equation, 4/3 , -1 Or, -1 , 4/3.
______________________________
Answer Verification
★Sum of roots = 1/3
==> 4/3 - 1 = 1/3
==> ( 4 - 3)/3 = 1/3
==> 1/3 = 1/3
L.H.S. = R.H.S.
That's Proved.
__________________
Corrected Question :-
- Find the zeroes of the quadratic polynomial 3x²-x-4 and verify the relationship between the zeroes and coefficient.
Answer :-
Given :-
- polynomial :=> 3x²-x-4.
To find :-
- Find the zeroes of the polynomial.
- Verify the relationship between the zeroes and coefficient.
Solution :-
⇒3x²-x-4 = 0
→splitting the middle term
⇒ 3x²+3x-4x-4 = 0
⇒ 3x(x+1)-4(x+1) = 0
⇒ x+1 = 0 , 3x-4 =0
⇒ x = 0-1 , 3x = 0+4
⇒ x = -1 , x = 4/3
→ Two zeroes of this polynomial are :⇒ -1 & 4/3
→ Let α= -1 β= 4/3
→Verification of relationship between the zeroes and coefficient.
⇒sum of zeroes = -b/a
⇒ α+β = -b/a
⇒ -1 + 4/3 = -(-1)/3
⇒ -3+4/3 = 1/3
⇒ 1/3 = 1/3
⇒product of zeroes = c/a
⇒ α×β = -4/3
⇒ -1 × 4/3 = -4/3
⇒ -4/3 = -4/3
→ Hence verified