Question

find the zeroes of the quadratic polynomial 4√3x^2+2√3x-2√3​

Answer 1

Step-by-step explanation:

$let \: p(x)= 4 \sqrt{3} {x}^{2} + 2 \sqrt{3} x - 2 \sqrt{3}$

zero of the polynomial is given by p(x)=0

$4 \sqrt{3} {x}^{2} + 2 \sqrt{3} x + 2 \sqrt{3} = 0$

$2 \sqrt{3} (2 {x}^{2} + x - 1) = 0$

therefore ,

$2 {x}^{2} + x + 1 = 0$

$2 {x}^{2} + x - 1 = 0$

2x^2 - 2x +x -1 = 0

2x(x - 1 ) +1 (x-1)=0

(2x+1 ) (x-1)=0

==》x = -1/2 ,1