Question

find the zeroes of the quadratic polynomial 4√3x^2 +4√3x-3√3​

Answer 1

Answer:

4√3x^2 +4√3x-3√3

Comparing the above equation with ax^2+bx+c=0 we get a=4√3, b=4√3, c=-3√3

b^2-4ac=(4√3) ^2-4(4√3)(-3√3)

=48-4(-36)

=48+144

=192

Using formula method,

x=-b±√(b^2-4ac)

2a

x =-(4√3)±√192

2(4√3)

x =4√3±√192

8√3

x =4√3±√(3×64)

8√3

x =√3[4±√64]

8√3

x =4±√64

8

x = 4±8

8

x =4+8

8

OR

4-8

8

x =12 OR -4

8 8

x =3 OR -1

2 2