Find the zeroes of the quadratic polynomial 4x^-4x-3 and verify the relation between zeros and coefficient
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Hii friend,
P(X) = 4X²-4X-3
=> 4X²-6X+2X-3
=> 2X(2X-3)+1(2X-3)
=> (2X-3) (2X+1)
=> (2X-3) = 0. OR (2X+1) = 0
=> 2X = 3. OR 2X = -1
=> X = 3/2. OR X = -1/2
Therefore,
Alpha = 3/2 and Beta = -1/2 are the two zeros of the polynomial 4X²-4X-3
Sum of zeros = (Alpha+Beta) = (3/2+(-1/2) = (3/2-1/2) = (3-1/2) = (2/2)= 1 = Coefficient of X/Coefficient of X².
Product of zeros = (Alpha × Beta) = (3/2×-1/2) = -3/4 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU....... :-)
P(X) = 4X²-4X-3
=> 4X²-6X+2X-3
=> 2X(2X-3)+1(2X-3)
=> (2X-3) (2X+1)
=> (2X-3) = 0. OR (2X+1) = 0
=> 2X = 3. OR 2X = -1
=> X = 3/2. OR X = -1/2
Therefore,
Alpha = 3/2 and Beta = -1/2 are the two zeros of the polynomial 4X²-4X-3
Sum of zeros = (Alpha+Beta) = (3/2+(-1/2) = (3/2-1/2) = (3-1/2) = (2/2)= 1 = Coefficient of X/Coefficient of X².
Product of zeros = (Alpha × Beta) = (3/2×-1/2) = -3/4 = Constant term/Coefficient of X².
HOPE IT WILL HELP YOU....... :-)
Answered by
0
Answer:
Step-by-step explanation:
P(X) = 4X²-4X-3
=> 4X²-6X+2X-3
=> 2X(2X-3)+1(2X-3)
=> (2X-3) (2X+1)
=> (2X-3) = 0. OR (2X+1) = 0
=> 2X = 3. OR 2X = -1
=> X = 3/2. OR X = -1/2
Therefore,
Alpha = 3/2 and Beta = -1/2 are the two zeros of the polynomial 4X²-4X-3
Sum of zeros = (Alpha+Beta) = (3/2+(-1/2) = (3/2-1/2) = (3-1/2) = (2/2)= 1 = Coefficient of X/Coefficient of X².
Product of zeros = (Alpha × Beta) = (3/2×-1/2) = -3/4 = Constant term/Coefficient of X².
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