Math, asked by luckyojha1159, 1 year ago

Find the zeroes of the quadratic polynomial 4x^-4x-3 and verify the relation between zeros and coefficient

Answers

Answered by Panzer786
9
Hii friend,

P(X) = 4X²-4X-3

=> 4X²-6X+2X-3

=> 2X(2X-3)+1(2X-3)

=> (2X-3) (2X+1)

=> (2X-3) = 0. OR (2X+1) = 0

=> 2X = 3. OR 2X = -1

=> X = 3/2. OR X = -1/2

Therefore,

Alpha = 3/2 and Beta = -1/2 are the two zeros of the polynomial 4X²-4X-3

Sum of zeros = (Alpha+Beta) = (3/2+(-1/2) = (3/2-1/2) = (3-1/2) = (2/2)= 1 = Coefficient of X/Coefficient of X².

Product of zeros = (Alpha × Beta) = (3/2×-1/2) = -3/4 = Constant term/Coefficient of X².


HOPE IT WILL HELP YOU....... :-)
Answered by hone2234hc
0

Answer:

Step-by-step explanation:

P(X) = 4X²-4X-3

=> 4X²-6X+2X-3

=> 2X(2X-3)+1(2X-3)

=> (2X-3) (2X+1)

=> (2X-3) = 0. OR (2X+1) = 0

=> 2X = 3. OR 2X = -1

=> X = 3/2. OR X = -1/2

Therefore,

Alpha = 3/2 and Beta = -1/2 are the two zeros of the polynomial 4X²-4X-3

Sum of zeros = (Alpha+Beta) = (3/2+(-1/2) = (3/2-1/2) = (3-1/2) = (2/2)= 1 = Coefficient of X/Coefficient of X².

Product of zeros = (Alpha × Beta) = (3/2×-1/2) = -3/4 = Constant term/Coefficient of X².

Similar questions