Question

Find the zeroes of the quadratic polynomial 4x²– 7.
​

Answer 1

Answer:

$\sqrt{7} /2 and -\sqrt{7} /2$

Explanation:

4x2 + 0x -7

=> 4x² + √28x - √28x - 7

=> √4x ( √4x + √7) - √7 ( √4x + √7)

=> (√4x-√7) ( √4x + √7)

=> the zeroes are √7/√4 and -√7/√4

=> √7/2 and -√7/2