Find the zeroes of the quadratic polynomial 5t^2+12t+7
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5t^2+12t+7
=5t^2+5t+7t+7
=5t(t+1)+7(t+1)
=(t+1)(5t+7)
=>t= - 7/5
or t= - 1
=5t^2+5t+7t+7
=5t(t+1)+7(t+1)
=(t+1)(5t+7)
=>t= - 7/5
or t= - 1
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