Question

find the zeroes of the quadratic polynomial 5t^2 + 12t + 7 and verify the relationship between the zeroes and the coefficients.

Answer 1

the answer I am solving on the paper........

Answer 2

Heya !!




5T² + 12T + 7



5T² + 7T + 5T + 7







T ( 5T + 7 ) + 1 ( 5T + 7 ) = 0





( 5T + 7 ) ( T + 1 ) = 0




( 5T + 7 ) = 0 OR ( T + 1 ) = 0




T = -7/5 or T = -1



Let alpha = -7/5 and Beta = -1





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Relationship between the zeroes and Coefficient.




Sum of zeroes = Alpha + Beta = -7/5 - 1 = -12/5 = -(Coefficient of X)/ ( Coefficient of X²)



And,



Product of zeroes = Alpha × Beta = -7/5 × -1 = 7/5 = Constant term / Coefficient of X2