Find the zeroes of the quadratic polynomial 5t2 + 12t + 7, and verify the
relationship between the zeroes and the coefficients.
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4
Answer:
Step-by-step explanation:
5t
2
+12t+7=0
5t
2
+5t+7t+7=0
5t(t+1)+7(t+1)=0
(5t+7)(t+1)=0
⇒t=
5
−7
and t=−1
∴ sum of roots is
5
−7
−1=
5
−12
=
a
−b
product of roots = (
5
−7
)(−1)=
5
7
=
a
c
Hence verified
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