Question

Find the zeroes of the quadratic polynomial 5x²-2 root 5x-3 and verify the
relationship between the zeroes and the co-efficients.​

Answer 1

5x 2 −2 5x −3

=5x 2 + 5x −3 5x −3

= 5x ( 5x +1)−3( 5x +1)

=( 5x −3)( 5x +1)

=x= 5

3 ,x=− 5

1Sum of zeroes = \frac{3}{\sqrt{5} } - \frac{1}{\sqrt{5} } = \frac{2}{\sqrt{5} }

53 − 51 = 52

Sum of roots = \frac{-b}{a} = a−b = \frac{2\sqrt{5} }{5} = \frac{2}{\sqrt{5} }

525 = 52

Product of zeroes = \frac{3}{\sqrt{5} } X -\frac{1}{\sqrt{5} } = -\frac{3}{5}

53 X− 51 =− 53

Product of roots= \frac{c}{a} =\frac{-3}{5}

ac = 5−3

Hence verified.

Mark as brainliest!!!!!!!!!!!