Question

Find the zeroes of the quadratic polynomial 5x2 + 8x – 4 and verify the relationship

between the zeroes and the coefficients of the polynomial.​

Answer 1

Answer:

5x^2+10x-2x-20=0

5x(x+2)-1(x+2)=0

(5x-1) (x+2)=0

5x=1 x= -2

x=1/5

Answer 2

Step-by-step explanation:

Given polynomial is 5x^2-8x-4

Here, a=5,b=−8 and c=−4

5x^2 −8x−4=5x^2 −10x+2x−4

=5x(x−2)+2(x−2)

=(x−2)(5x+2)

So, the value of 5x^2 −8x−4 is zero when x=2 or x= -2/5

Therefore , the zeroes of 5x^2−8x−4 are 2 and -2/5.

Now, sum of zeroes =2+( −2/5)=(8/5)=-b/a.

product of zeroes =2×(−2/5)= −4/5 = c/a.

Hence verified.

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