Question

Find the zeroes of the quadratic polynomial 6x - 13x + 6 and verify the relation between the zeroes and its coefficients.
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Answer 1

Given:

6x - 13x + 6

To find out:

Find the zeroes of polynomial and verify the relation between the zeroes and the coefficient of given polynomial.

Solution:

We have,

6x² - 13x + 6

= 6x² - 4x - 9x + 6

= 2x ( 3x - 2 ) - 3 ( 3x - 2 )

= ( 3x - 2 ) ( 2x - 3 )

So, to find zeroes of polynomial: 6x² - 13x + 6 will be zero, hence ( 3x - 2 ) = 0 and ( 2x - 3 ) = 0.

So

x = 2/3 and x = 3/2

Therefore, the zeroes of : 6x² - 13x + 6 are 2/3 and 3/2.

Sum of the zeroes = 2/3 + 3/2

= 4 + 9/6

= 13/6

=> -(-13)/6 = - coefficient of x / coefficient of x²

Product of the zeroes = 2/3 × 3/2

=> 6/6 = constant term/ coefficient of x²

Verified.

Answer 2

Answer:

same as.. above my phone