Find the zeroes of the quadratic polynomial 6x*2 - 7x-3
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Step-by-step explanation:
= 6x*2 - 7x - 3=0
= 6x*2 - (9-2)x - 3 =0
= 6x*2 - 9x +2x - 3=0
= 3x(2x-3) +1(2x-3)=0
= (3x+1) (2x-3)=0
= 3x= - 1 , 2x= 3
= x= - 1/3 , x = 3/2
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