Find the zeroes of the quadratic polynomial 6x^2 - 7x - 3 and verify the relationship between the zeroes and coefficients.
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6x²-7x-3=0
=6x²-9x+2x-3=0
=3x(2x-3) +1(2x-3)=0
=(3x+1)(2x-3)=0
α=-1/3
β=3/2
∴α+β= -coefficient of x/coefficient of x²
=>-1/3+3/2=-(-7/6)
=>7/6=7/6
∴αβ=constant/coefficient of x²
=>-1/3 ×3/2=-3/6
=>-1/2=-1/2
=6x²-9x+2x-3=0
=3x(2x-3) +1(2x-3)=0
=(3x+1)(2x-3)=0
α=-1/3
β=3/2
∴α+β= -coefficient of x/coefficient of x²
=>-1/3+3/2=-(-7/6)
=>7/6=7/6
∴αβ=constant/coefficient of x²
=>-1/3 ×3/2=-3/6
=>-1/2=-1/2
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