find the zeroes of the quadratic polynomial 6x2 +13x-5 and verify the zeroes and coefficient
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We have p(x) = x2 – 2x – 8
= x2 + 2x – 4x – 8 = x (x + 2) – 4 (x + 2)
= (x – 4) (x + 2)
For p(x) = 0, we have
(x – 4) (x + 2) = 0
Either x – 4 = 0 ⇒ x = 4
or x + 2 = 0 ⇒ x = – 2
∴ The zeroes of x2 2x – 8 are 4 and –2.
Now, sum of the zeroes
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