Question

Find the zeroes of the quadratic polynomial 6x2 – 3 – 7x

Answer 1

Answer:

Given,

6x²-7x - 3

To find the zeroes of the polynomial,

6x²-7x - 3 = 0

6x²-9x +2x -3 = 0

3x(2x-3) + 1(2x -3) = 0

(3x+1) (2x-3) = 0

x = -1/3 or 3/2

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Answer 2

Answer:

6x2 - 7x - 3

Sum = -7

Product =-18

Hence factors = -9 and 2

6x2 + 2x -9x -3 = 0

2x(3x +1 ) -3 ( 3x +1) = 0

(2x-3)(3x+1) =0

2x-3 = 0 ; 3x+1 =0

X = 3/2 and -1/3