Question

Find the zeroes of the quadratic polynomial 6x2 – 3 – 7x and verify the relationship between the zeroes and the coefficient of the polynomial.

Answer 1

Answer:

Step-by-step explanation:

6x²-7x-3

=6x²+2x-9x-3

=2x(3x+1)-3(3x+1)

=(2x-3)(3x+1)

⇒2x-3=0                                              ⇒ x= - 1/3

α=3/2 ,β= - 1/3

⇒α+β= -b/a

⇒3/2+(-1/3)= - (-3)/6

⇒3/2-1/3=1/2

⇒7/6 =1/2

⇒αβ=c/a

⇒ 3/2(-1/3)= -7/6

⇒-1/2= -7/6

⇒1/2=7/6