FIND The ZEROES OF THE Quadratic
polynomial
6x² - 7x-5
Answers
Answered by
1
Answer:
for the zeros we must do factorization
so,
6x^2-7x-5
=6x^2-(10-3)x-5
=6x^2-10x+3x-5
taking common
=2x(3x-5)+1(3x-5)
=(3x-5)(2x+1)
for zeros
3x-5=0 and 2x+1=0
3x=5 2x=-1
x=5/3 x=-1/2
therefore zeros are 5/3 and -1/2
Step-by-step explanation:
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Answered by
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Answer:
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