Find the zeroes of the quadratic polynomial 7 2 − 11 3 − 2 3 and verify the relationship between the zeroes and their coefficients.
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Answered by
1
Step-by-step explanation:
Multiply the eq by 3
21y2-11y-2=0
21y2-14y+3y-2=0
7y(3y-2)+1(3y-2)=0
(7y+1)(3y-2)=0
y=-1/7 and y = 2/3
a=7 b=-11/3 c=-2/3
sum of roots is -1/7+2/3=11/21 =-b/a
product of root=-2/21=c/a
Answered by
6
- Multiplying both sides by 3.
Let alpha be 2/3 and beta be -1/7.
In Quadratic Equation 7x²-11x/3-2/3=0
On comparing with ax²+bx+c=0
Verified
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