Question

Find the zeroes of the quadratic polynomial: 9 - x2.

Answer 1

Answer:

Zeroes are 3 and - 3

Step-by-step explanation:

Given :

p ( x ) = 9 - x²

Rewrite as :

= > 3² - x²

Using identity :

a² - b² = ( a + b ) ( a - b )

= >  3² - x²

= > ( 3 - x ) ( 3 + x )

Now zeroes of polynomial :

3 - x = 0

= > x = 3

OR

3 + x = 0

= > x = - 3

Therefore , zeroes of quadratic polynomial 9 - x² are 3 and - 3 .

Answer 2

Here the two zeroes are =-3&+3