Question

find the zeroes of the quadratic polynomial abx2 + (b2-ac)x-bc

Answer 1

abx2 + (b2-ac)x-bc = abx^2+b^2x-acx-bc = bx(ax+b)-c(ax+b) = (ax+b)(bx-c) Zeros are -b/a and c/b

Answer 2

The zeroes of the quadratic polynomial are -b/a and c/b

Step-by-step explanation:

The given polynomial

$p(x)=abx^2+(b^2-ac)x-bc$

To find the zeroes of the polynomial

$p(x)=0$

$\implies abx^2+(b^2-ac)x-bc=0$

or, $abx^2+b^2x-acx-bc=0$

or, $bx(ax+b)-c(ax+b)=0$

or, $(ax+b)(bx-c)=0$

$\impies x=-\frac{b}{a}, x=\frac{c}{b}$

Therefore, the zeroes of the polynomial p(x) are -b/a and c/b

Hope this answer is helpful.

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